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Solar Panel Count Calculator

How many panels to cover your usage — by monthly kWh, sun hours, and panel wattage.

Updated

900 kWh
4.5 h/day
80%

You need

21panels

a 8.4 kW system at 400 W each

System size needed
8.3 kW
Installed size (rounded up)
8.4 kW
Rough roof area
~378 sq ft

In short

How many solar panels do I need?

Required kW = (monthly kWh ÷ 30) ÷ (peak sun hours × efficiency). For 900 kWh a month at 4.5 peak sun hours and 0.80 losses that is 8.33 kW, which at 400 W a panel is 20.8 panels, rounded up to 21 for an installed 8.4 kW system. Step up to 450 W panels and 19 cover the same usage.

The count covers your energy, not your roof: shading, orientation, vents and code setbacks all decide whether those panels physically fit, which is an installer job.

How to use the solar panel count calculator

Enter your monthly electricity usage in kilowatt-hours, your area peak sun hours, the wattage of the panels you are considering, and a losses factor, and the tool returns the system size you need and the number of panels that delivers it. Your monthly kilowatt-hours is printed on every electricity bill, and averaging a full year of them gives the steadiest figure to size around.

There is no rate field here on purpose: this tool sizes the array, and the solar panel output calculator is where your own dollars-per-kilowatt-hour turns that array into money. Keeping the two separate stops a high electricity rate from quietly flattering a system size it has nothing to do with.

8.33 kW

System required

900 kWh a month at 4.5 sun hours, 0.80 losses

21 panels

At 400 W each

always rounded up to whole panels

378 sq ft

Usable roof needed

about 18 square feet a panel

Usage is the foundation, so the count is only ever as good as the number you enter. A single month can mislead badly in either direction. Summer air conditioning or winter electric heat can push one bill far above your norm, and a mild shoulder month can sit well below it.

A twelve-month average sizes a system for the whole year, which is what most people actually want. If your goal is a full offset, average the year. If you only want to shave the expensive peaks off a tiered or time-of-use tariff, size to a typical month instead and accept that you will import in the heavy ones.

National context helps here: the EIA reported an average of about 863 kWh a month per US residential customer in 2024, with state averages ranging from roughly 500 to over 1,200.

The count always rounds up, for the obvious reason that you cannot install 20.8 panels. Rounding up fully covers the target, which is also why the installed system size comes out slightly above the bare requirement — 21 panels at 400 W is 8.4 kW against an 8.33 kW need.

That small oversize is welcome rather than wasteful, because panels degrade slowly over a 25 year service life and an array sized exactly to today usage will fall short of it later.

Panel wattage is the other lever worth thinking about. Higher-wattage panels cover the same energy in fewer units and less roof, which matters on a small or cut-up roof, while the total system size barely moves. Enter the wattage you are genuinely being quoted.

Do

  • Average a full twelve months of bills before sizing anything.
  • Enter the nameplate wattage of the panels you are genuinely being quoted.
  • Confirm your own address in NREL PVWatts rather than sizing from a state figure.
  • Let the count round up, since the small oversize covers years of slow degradation.

Don't

  • Size the array from a single summer or winter bill.
  • Size to a typical month if a full offset is what you actually want.
  • Read the roof area figure as a layout, because vents, valleys and setbacks all eat into it.
  • Chase a full offset where exported energy is credited below the retail rate.

Fourteen states, each with its own household electricity appetite and its own sunshine, run through the same sizing formula. The two columns fight each other in interesting ways: Arizona uses more electricity than Ohio and still needs fewer panels, while Washington and Louisiana land on identical panel counts for completely opposite reasons.

StateAverage household use per month (kWh)Peak sun hours per daySystem size needed at 0.80 lossesPanels at 400 W each
Louisiana1,202 kWh4.710.66 kW27 panels
Tennessee1,154 kWh4.410.93 kW28 panels
Alabama1,143 kWh4.610.35 kW26 panels
Florida1,104 kWh5.38.68 kW22 panels
Texas1,096 kWh5.38.62 kW22 panels
Arizona1,075 kWh6.56.89 kW18 panels
Georgia1,074 kWh4.89.32 kW24 panels
Virginia1,032 kWh4.59.56 kW24 panels
Washington955 kWh3.810.47 kW27 panels
United States average863 kWh4.57.99 kW20 panels
Ohio846 kWh4.18.60 kW22 panels
Illinois693 kWh4.36.72 kW17 panels
Michigan618 kWh4.06.44 kW17 panels
California503 kWh5.63.74 kW10 panels
Average monthly household consumption is EIA 2024 residential data; peak sun hours are annual state averages from NREL PVWatts data drawn from the National Solar Radiation Database, both retrieved July 2026. System sizes and panel counts are computed here at an 0.80 losses factor with 400 W panels, rounding up to whole panels. Your own usage and your own address will both differ from a state average.

Will those panels actually fit the roof?

For a rough physical check, a standard residential panel around 400 W measures roughly 65 by 39 inches, which is about 17.6 square feet, so multiplying the panel count by about 18 square feet gives the usable roof area the array would need. The tool shows this figure.

Treat it strictly as a gut check on whether the roof is in the right ballpark, not as a layout: real installations lose space to vents, chimneys, hips, valleys, shading, and the setbacks that local fire codes require around roof edges and ridges. Let a licensed installer do the shading, orientation and structural work before anything is ordered.

See what that sized system would make

Pair the result with the solar panel output calculator to see what the array you just sized would actually produce across a day, a month and a year.

Open the solar output calculator
The three-line panel count formula The three-line formula Usage sets the requirement, the sun sets what a kilowatt is worth, wattage converts it to panels REQUIRED SYSTEM SIZE (monthly kWh ÷ 30) ÷ (sun hours × efficiency) 30 ÷ 3.6 = 8.33 kW PANEL COUNT required kW × 1000 ÷ panel watts, rounded up 8,333 ÷ 400 = 20.8 → 21 INSTALLED SYSTEM panels × panel watts ÷ 1000 21 × 400 ÷ 1000 = 8.4 kW Installed 8.4 kW sits just above the 8.33 kW required — the round-up is your margin
Daily kWh / sun hours / panel watts -> the panel count.

The formula, worked line by line

The chain runs from energy to hardware in three steps. Divide monthly usage by 30 to get a daily energy target. Divide that by what one kilowatt of panels actually delivers in a day at your site, which is peak sun hours times the loss factor, to get the system size in kilowatts. Then divide the system size by the wattage of one panel to get the count, and round up, because panels come in whole units.

The middle term is doing the interesting work. Peak sun hours times efficiency is the daily yield per installed kilowatt: 4.5 sun hours at 0.80 gives 3.6 kWh per kW per day, while 6.5 sun hours at the same losses gives 5.2. Because that value sits in a denominator, sunshine and system size are inversely related, which is why the sunniest states in the table need the fewest panels despite far from the lowest consumption.

required kW = (monthly kWh ÷ 30) ÷ (peak sun hours × efficiency)
panels = round up( required kW × 1000 ÷ panel watts )
installed system kW = panels × panel watts ÷ 1000
roof area ≈ panels × 18 sq ft for a 400 W panel
Panels needed for the monthly usageCovering 900 kilowatt-hours a month needs a 8.3 kilowatt system, which is 21 panels of 400 watts each.21 × 400 W PANELSUSAGE → SYSTEM → PANELSmonthly use900 kWhsystem needed8.3 kWpanels (round up)21
Covering 900 kWh a month needs an 8.33 kW system — 21 panels at 400 W each.
The worked default, energy to hardware
Daily target
900 ÷ 30 = 30 kWh
Daily yield per installed kW
4.5 × 0.80 = 3.6 kWh
System required
30 ÷ 3.6 = 8.33 kW
Panels at 400 W
8,333 ÷ 400 = 20.8
Rounded up
21 panels, an installed 8.4 kW system

At roughly 18 square feet a panel, 21 panels occupy about 378 square feet of usable roof.

The same 900 kWh a month, at three panel wattages(panels required)
350 W panels24 panels, 8.4 kW
400 W panels21 panels, 8.4 kW
450 W panels19 panels, 8.55 kW

Read it: The system size barely moves in either direction while the count and the roof area move a lot, which is exactly why higher-wattage panels are the answer when roof space rather than budget is the binding constraint.

Raise the usage to 1,200 kWh a month instead and the requirement becomes 11.11 kW, or 28 panels at 400 W for an installed 11.2 kW.

Questions people ask

How many solar panels do I need for a typical home?

For a home using 900 kWh a month at 4.5 peak sun hours with 400 W panels and an 0.80 losses factor, about 21 panels, which is an installed 8.4 kW system. The count scales directly with your usage and inversely with your sun hours, so the same consumption in a 6.5 sun-hour state needs far fewer. For national context, the EIA put average US residential consumption at roughly 863 kWh a month in 2024, but state averages run from about 500 to over 1,200, so enter your own figure.

Covered in depth in How Many Solar Panels Do I Need? Sizing From Your Real Usage

How many panels do I need for 1,200 kWh a month?

About 28 standard 400 W panels at 4.5 peak sun hours and an 0.80 losses factor. The requirement works out at 11.11 kW, which is 27.8 panels, rounded up to 28 for an installed 11.2 kW system. Higher usage needs proportionally more panels, so the relationship is straightforwardly linear. If roof space is tight, stepping up to 450 W panels covers the same 1,200 kWh in 25 panels instead, taking roughly 54 square feet less roof for essentially the same system size.

Does panel wattage change how many panels I need?

Yes, and much more than it changes the system size. For the same 900 kWh a month, 450 W panels need 19, 400 W panels need 21, and 350 W panels need 24. The installed kilowatts stay within a few percent of each other across all three, because the energy requirement has not changed. What changes is the number of units on the roof and the area they occupy, which is why higher-wattage panels are the standard answer when roof space rather than budget is the constraint.

Why does the panel count always round up?

Because you can only install whole panels, and rounding down would leave the array short of the usage it was sized to cover. Rounding up guarantees full coverage and leaves a small margin, which is genuinely useful rather than wasteful: panels lose a fraction of their output every year across a 25 year service life, so an array sized exactly to today consumption will fall short of it in a decade. That rounding is also why the installed system size always lands slightly above the bare kilowatt requirement the tool reports.

How much roof space will the panels need?

A standard residential panel of around 400 W measures roughly 65 by 39 inches, which is about 17.6 square feet, so 21 panels need approximately 378 square feet of usable roof. Higher-wattage panels pack more output into a similar footprint and lower the total area. Treat this as a rough check only. Real layouts lose space to vents, chimneys, hips and valleys, to shading from trees and neighbouring roofs, and to the setbacks local fire codes require around roof edges and ridges, which an installer maps out on site.

Sources

Where the constants and formulas on this page come from. Each line names the figure it backs.

  1. The average monthly kWh per US residential customer and the state-by-state spread this page sizes systems against.

    Electric Sales, Revenue, and Average Price — Table 5.A, residential average monthly bill and consumptionUS Energy Information Administration, 2024 data, released 7 October 2025

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